Problem 1: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Especially when somebody already pointed out the problem in her code. The sum of these multiples is . Project Euler Problem 1 Statement. The series, 1 1 + 2 2 + 3 3 + … + 10 10 = 10405071317.. Find the last ten digits of the series, 1 1 + 2 2 + 3 3 + … + 1000 1000.. – Fabinout Jan 29 '14 at 16:24 C++ solution to Project Euler Problem 1. \$\begingroup\$ BTW it would be best to include the specification of the project Euler problem 1 in your question if you implemented the problem solution as stated in project euler. A more mathematical way to solve the first problem in the project Euler archives. I suppose that Euler_Project are for getting better at programming, I don't think you should handle answers as easily as you did. I'm learning C++ and currently doing Project Euler challenges. Leaderboard. Project Euler is a teaching resource. The sum of these multiples is 23. Please be sure to answer the question. The sum of these multiples is 23. Submissions. … Project Euler #1: Multiples of 3 and 5. Although mathematics will help you arrive at elegant and efficient methods, the use of a computer and … Viewed 11 times 1 $\begingroup$ Okay so the problem itself is really simple, If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. Ask Question Asked today. Project Euler (projecteuler.net) is a series of challenging mathematical/computer programming problems that will require more than just mathematical insights to solve. Since you have a generalized solution, you should provide your generalized specification of the problem. Make an attempt, then come back with specific questions about any difficulties you're having. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. ... but it was the Project Euler forums that showed me the formula to do it. If a box contains twenty-one coloured discs, composed of fifteen blue discs and six red discs, and two discs were taken at random, it can be seen that the probability of taking two blue discs, P(BB) = (15/21)×(14/20) = 1/2. We won't just give you a solution - what would you learn if we did? If we list all the natural numbers below that are multiples of or , we get and . The first challenge is the following. Project Euler solutions Introduction. Problem. I solve Project Euler problems to practice and extend my math and programming skills, all while having fun at the same time. If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. This problem is a programming version of Problem 1 from projecteuler.net. Here I make my solutions publicly available for other enthusiasts to learn from and to critique. – Tangentially Perpendicular 15 mins ago The sum of these multiples is 23. Discussions. The sum of these multiples is 23. 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